Plz 20 points Q, help me quickly , thnkss?

Two crates, one with mass 4.00 {\rm kg} and the other with mass 6.00 {\rm kg}, sit on the frictionless surface of a frozen pond, connected by a light rope View Figure . A woman wearing golf shoes (so she can get traction on the ice) pulls horizontally on the 6.00 {\rm kg} crate with a force F that gives the crate an acceleration of 2.20 m/s^2.





a) What is the acceleration of the 4.00 {\rm kg} crate?





b)Use Newton%26#039;s second law to find the tension T in the rope that connects the two crates.





c)Which is larger in magnitude, force T or force F?





d)Use part (C) and Newton%26#039;s second law to calculate the magnitude of the force F.





Thanks, .. :(

Plz 20 points Q, help me quickly , thnkss?
a) Also 2.20 m/s^2.


She has to move the whole mass, and because the rope it tight, it has to move at the same speed as the larger block





b) This the ammount of force needed to accelerate the second block at 2.20 m/s^2. Newton second law of motion says:





F= M*a, --%26gt;


F = 4 * 9.81 * 2.2


F = 86.328 Newton





c) F is larger, because it has to move 10kg, T only has to move 4 kg.





d)


F= M*a, --%26gt;


F = 10 * 9.81 * 2.2


F = 215.82 Newton





You have to use Weight * g (g=9.81) because you need the force in Newton, not kg.



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