Use Newton's second law to find the tension in the rope that connects the two crates.?

Two crates, one with mass 4.00 kg and the other with mass 6.00 kg, sit on the frictionless surface of a frozen pond, connected by a light rope . A woman wearing golf shoes (so she can get traction on the ice) pulls horizontally on the 6.00-kg crate with a force that gives the crate an acceleration of 3.00 m/s^2. What is the acceleration of the 4.00-kg crate?Use part (C) and Newton%26#039;s second law to calculate the magnitude of the force .

Use Newton%26#039;s second law to find the tension in the rope that connects the two crates.?
Suppose the force exerted by the woman on 6 kg crate is F.





As both the crates are connected by a string , both crates will have same acceleration that is 3.00 m/s^2





If T is tension in the connecting string, then for acceleration of 6.00 kg crate, the equation of motion is,





F - T=6.00x3.00=18.0





F=T+18--------------(1)





for acceleration of 4.00 kg crate, the equation of motion is,





T =4.00x3.00 =12.0





T=12----------------(2)





from equations (1) and (2)





F=30 N





The woman exerts 30 N force to pull the 6.00 kg crate connected by a string to a 4.00 kg crate



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