What is the acceleration of the 4.00 crate?

Two crates, one with mass 4.00 and the other with mass 6.00 , sit on the frictionless surface of a frozen pond, connected by a light rope . A woman wearing golf shoes (so she can get traction on the ice) pulls horizontally on the 6.00 crate with a force that gives the crate an acceleration of 2.00 .

What is the acceleration of the 4.00 crate?
F=m*a


4.00kg (convert to grams)=4000g


6.00kg (convert to grams)=6000g


(4000g+6000g)*2.00m/s=20000gm/s
Reply:Since both crates are joined with Tension from the rope the Force needed must be enough to pull both... And it is since both accelerate...





Newtons Second Law:


F= m x A then,





6+4kg x 2m/s^2 = 20





20N
Reply:The force she applies to the 6.00 mass crate also ahs to accelerate the 4.00 mass crate


F = m*a


F = 10*2 = 20N


Magnitude of total force = 20N





Tension in rope joining the two crates:


The 4.00 mass crate has an acceleration of 2.0m/S²


F=m*a


F = 4.00*2


F=8N


Tension in rope is 8N



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