Two crates, one with mass 4.00 {\rm kg} and the other with mass 6.00 {\rm kg}, sit on the frictionless surface of a frozen pond, connected by a light rope View Figure . A woman wearing golf shoes (so she can get traction on the ice) pulls horizontally on the 6.00 {\rm kg} crate with a force F that gives the crate an acceleration of 2.20 m/s^2.
a) What is the acceleration of the 4.00 {\rm kg} crate?
b)Use Newton%26#039;s second law to find the tension T in the rope that connects the two crates.
c)Which is larger in magnitude, force T or force F?
d)Use part (C) and Newton%26#039;s second law to calculate the magnitude of the force F.
Thanks, .. :(
Plz Help me !! Physics Tension %26amp; Force Q 20 points :(?
the force is 10^18=12^ with velocity of 20.500 mega zooms.
Reply:a) Assuming the rope doesn%26#039;t stretch, the acceleration of the 4kg mass is the same as the acceleration for the 6kg mass, is 2.20 m/s^2
b) The tension T is F = ma = 4.00kg * 2.2 m/s^2 = 8.8 N
c) F %26gt; T
d) F=10.0kg*2.2m/s^2 = 22 N
under my skin
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